Ok, I have a few questions that are kinda challenging so if you are good at this kind of thing plz help.


1.

Let tn equal the integer closest the √n

For example, t₁ = t₂ = 1 since √1=1 and √2=1.41 and t₃=2 since √3=1.71.

What is the sum of the following?
1/t₁ + 1/t₂ + 1/t₃ + 1/t₄ + ... + 1/t₂₀₀₈ + 1/t₂₀₀₉ + 1/t₂₀₁₀






2.
Alex chose positive integers a, b, c, d, e, f and completely multiplied out the polynomial product

(1 - x)^a(1 + x)^b(1 - x + x²)^c(1 + x²)^d(1 + x + x²)^e(1 + x + x² + x³ + x⁴)^f

After she simplified her result, she discarded any term involving x to any power greater than 6 and was astonished to see that what was left was 1 - 2x. If a > d + e + f and b > c + d and e > c, what value of a did she choose?

are you kidding me?

5 obviously

froggie you should consider joining xpt, we need someone who makes the place less gloomy

haha, but this was a serious question.

1. answer is 88+(2/3) I too lazy too further simplify for u.
(1/t1 + 1/t2)= 1+1=2
(1/t3 + 1/t4...1/t6)= 2
sum of all even numbers (2, 4, 6, 8,...)=2010 ( 2 (1's), 4 (1/2)'s, 6 (1/3)'s etc...)
2-88 sum of every even integer is 1980
2010-1980= 30
30* (1/45)<---- (90/2 gets u the 45 denominator) (total of 90 (1/45)s)=2/3
2* 44(integers from 2-88 the even ones)=88
sum= 88 and two thirds.

feel free to flame me if i do this wrong
im to lazy to help u out on #2 if u really need help ill try to do it 4 u.

2nd question i think A=4 not sure :/.

Thx for help, I got to the part where 2-88 was 1980 then I didn't know what to do with the 30 that was left. I didn't even know where to start with the second one so I thought I'd see if someone else knew how to get it. Thanks.

is this yr homework????

Sorta not rlly. It was on a big thing of questions we were supposed to look at.

retard...

I feel like he posted this just to show off.

e=mc^2?

out of all the people I'm glad froggie dude doesnt come on here anymore

I disagree, it was nice to have another ESO player here

I didnt know him tho he seems a pretty chilled guy